Question

Three balls, with masses of 3m,2m and m, are fastened to a massless rod of length L. The rotational inertias about the ledt

Answer 1

I = MR^2

The Attempt at a Solution:::

I total = (3M)(0)^2 + (2M)(L/2)^2 + (M)(L)^2

I total = 3ML^2/2

It says the answer is 3ML^2/4 though.

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Answer 2

The rotational inertia about the left is $3ML^{2} /2$.

What is meant by inertia?

• Inertia, property of a body by virtue of which it opposes any agency that attempts to put it in motion or, if it is moving, to change the magnitude or direction of its velocity.
• Inertia is a passive property and does not enable a body to do anything except oppose such active agents as forces and torques.

To calculate the rotational inertia about the left

$I = I1 + I2 + I3\\ I= 3M(0^{2}) + 2M(L/2 )^{2} + M(L)^{2} \\I = 3ML^{2} /2$

The rotational inertia about the left is $3ML^{2} /2$

To learn more about Inertia refer:https://brainly.com/question/18113232

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