Question

What's the total resistance of a circuit that contains three 30 Ω resistors connected in series

Answer 1

Answer:

The total resistance is 90 Ω

Explanation:

When the circuit are connected in the series then we can determined the total resistance of the circuit by the formula that are mention below .

$R=R1+ R2 +R3$   -------Equation 1

Here $R1=R2=R3=30 \ ohm$

Now putting the value of R1, R2 and R3 in the Equation  1

So

$R=30 + 30 + 30$

Therefore the total resistance of the circuit =90 Ω