Respuesta :

Answer:

x=2

Step-by-step explanation:

triangle area is 1/2BH

1/2(4x)=4

2x=4

x=2 units

Answer:

Missing side = 2

X= 2

Have given details if x was only base of the side triangle

This is in order to find a completely new triangle with just the height and in order to find and combine 1 given area say if just the right side in your diagram was 4 and we had to find the other triangle. This is only done on scale or 1 given measure or angle for the right side triangle. We was not given this but proved a 0.3 scale.

Area of other triangle =2.66^2

2.66+4 combined = 6.66^2

Step-by-step explanation:

We find a square height is also 4

We also know a right angle triangles height can be found using either 1/2 base or 1/2 height.

So this can mean the height is and stays 4 and the base is 2.

As 1/2  4 height = 2 height

2 unit height x 2 unit base = 4

Therefore, the first triangle slant is the same.

4sq +2sq = c^2

√16+√4 = √20

c^2 = √20 = 4.47     = 4.472135955

c = 4.47 slant

Given a=4 and c=4.47,

b = 1.99522

∠α = 63.49° = 63°29'23"

∠β = 26.51° = 26°30'37"

h = 1.78543

We cna tell now that the triangle is 0.333 smaller so the measurements

Show 2/3 of 2 = 1.333 being the base across

using this as Area we find 1.333 x 2 =  2.666

(1/2 h^b of 4) =2

We can prove with the angles

63 +27 degree or

a^2+b^2 = c^2

1.333^2 + 4^2

= √1.776889+√ 16 = √ 17.776889

c^2 = 4.21626481616

c= 4.22 slant left side  (nb right side on attachment)

Angle ∠ A = α = 71.478° = 71°28'39″

Angle ∠ B = β = 63.53° = 63°31'48″

Angle ∠ C = γ = 44.992° = 44°59'33″

We see 63 angle on right lower side of attachment picture in reflection and can prove x = 3.333

But on your diagram base x = 2

What i have done is enlarged x by 0.3 and proven  how to find x if x was just one side of the triangle's height.

The triangles even though reflected are identical.

Other info is proven through finding ha and hb heights.

We confirm 4.001 is the hc height of your diagram.

Height: ha = 2.984

Height: hb = 3.16

Height: hc = 4.001

Ver imagen bamboola1