Question

to move a box you pull on the handle as indicated in the diagram shown below with a constant force f. the mass of the box is m = 8 kg and the angle ������ = 22°. what is the magnitude of the normal force?

Answer 1

The magnitude of the normal force is 63.42 N

A normal force is a force that is perpendicular to the surface in contact.

From the diagram, The normal force is given below.

• N = mg-Fsin∅..................... Equation 1

⇒ Where:

• N = Normal force.
• m = mass of the box.
• F = Force used to move the box.
• ∅ = Angle to the horizontal.
• g = constant = acceleration due to gravity.

From the question, Assuming the Force that pulls the box is F = 40 N

⇒ Given:

• F = 40 N
• m = 8 kg
• ∅ = 22°
• g = 9.8 m/s²

Substitute these values into equation 1

• N = [8(9.8)]-(40sin22°)
• N = 78.4-14.984
• N = 63.42 N

Hence, The magnitude of the normal force is 63.42 N

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