Answer:
130m/s^2 and 1.22s
Explanation:
From V = u+at
Where V, u, a, and t are the final velocity, initial velocity, acceleration and time respectively.
v = 6.75m/s
u = 3.5m/s
t = 0.250secs
a = ?
V = u+at
6.75= 3.5+a(0.250)
6.75-3.5 = 0.250a
3.25=0.250a
Divide both sides by 0.250
3.25/0.250= 0.250a/0.250
a = 130m/s^2
The acceleration of the will be 130 meter per second
Question 2
Speed = distance/time
Given that speed= 4.25m/s
Distance = 5.2m and time = ?
4.25m/s = 5.2m/t
Cross multiply
4.25×t = 5.2
Make t the subject by dividing both sides by 4.25
4.25t/4.25 = 5.2/4.25
t = 1.22s
Hence the time taken will be 1.22 seconds
