Answer:
[tex]V_2=11.35L[/tex]
Explanation:
Knowing that the system is at constant pressure, the energy balance is:
[tex]\Delta H=Q-W[/tex]
If all the energy (enthalpy of combustion) is transformed into work:
[tex]\Delta H=-W[/tex]
Work:
[tex]W=-\int_{V1}^{V2}P*dV[/tex]
[tex]W=-P*(V_2-V_1)[/tex]
[tex]\Delta H=P*(V_2-V_1)[/tex]
Calculating:
[tex]935J=84659 Pa*(V_2-3.1*10^{-4}m^3)[/tex]
[tex]V_2=0.0113 m^3=11.35L[/tex]