One option in a roulette game is to bet $ 6


on red. ​ (There are 18 red​ compartments, 18 black​ compartments, and two compartments that are neither red nor​ black.) If the ball lands on​ red, you get to keep the $ 6


you paid to play the game and you are awarded $ 6

.

If the ball lands​ elsewhere, you are awarded nothing and the $ 6


that you bet is collected

Respuesta :

Answer:

We have 47% of chances to win those six bucks.

Step-by-step explanation:

In this problem we need to find the probabilty of winning thos $6.

According to the problem, we win $6 if we hit one red. We know that there are 18 red compartments, 18 black compartments and 2 neither red nor blakc, for a total of 38 compartments.

We need to use the standard probabilty definition which is the ratio between the number of events and the total number of outcomes. So,

[tex]P=\frac{18}{38} \approx 0.47[/tex]

Which is equivalent to 47% of chances.

Therefore, we have 47% of chances to win those six bucks. (The Casino has the odds in their favor)

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