Answer:
0.1371 * 10 ^ -27 kg
Explanation:
From the question number of hydrogen nuclei used to form 3 Helium nuclei = 12 ( 4 * 3 )
mass of the 12 hydrogen nuclei = 12 *( 1.6726 *10^-27) = 20.0712 * 10 ^-27
mass of single helium = 6.6447 * 10 ^-27 kg
therefore the mass of the 3 helium = 3 *( 6.6447 *10 ^-27) = 19.9341 * 10 ^-27 kg
The mass difference between the hydrogen and the helium used
= (20.0712 * 10^ -27) - (19.9341 * 10 ^-27) = 0.1371 * 10 ^ -27 kg
therefore 0.1371 * 10^-27 kg is converted into energy to create the three helium nuclei