Question

Rewrite the equation by completing the square. X2−2x+1=0x^{2}-2x+1 = 0x2−2x+1=0x, squared, minus, 2, x, plus, 1, equals, 0 (x+(x + {}(x+left parenthesis, x, plus )2=)^2 = {})2=right parenthesis, squared, equals

Answer 1

Answer:

$(x-1)^2=0$

Step-by-step explanation:

Given: $x^{2}-2x+1 = 0$

To rewrite the quadratic equation by completing the square, we follow these steps.

Step 1: Take the constant to the right hand side

$x^{2}-2x=-1$

Step 2: Divide the coefficient of x by 2

$-\dfrac{2}{2}=-1$

Step 3: Square your result from Step 1

$(-1)^2$

Step 4: Add the result form step 2 to both sides of the equation

$x^2 -2x+(-1)^2 = -1+(-1)^2$

Step 5: Rewrite the Left hand side in the form $(x+k)^2$

$(x-1)^2=1+1\\(x-1)^2=0$

Therefore, the equation written by completing the square is:

$(x-1)^2=0$

Answer 2

Answer:

(x+3/2) ^2= 121/4

Step-by-step explanation: