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Answer:
[tex]\angle YPR = 42^o[/tex]
Step-by-step explanation:
Its given:
[tex]\angle FPY = 90^o \\ \angle YPR + \angle FPR = 90^0 \\ 4p + 80 + 5p + 82 = 90^o \\ 9p = -72^o \\ p = -8 \\ \\ \angle YPR = 5(-8) + 82 = 42^o[/tex]