Axis of symmetry of f(x) is at x=4
Axis of symmetry for h(x) is at x=-2
Given :
[tex]f(x) = -2(x - 4)^2+ 2[/tex]
The given f(x) is in the form of f(x)=a(x-h)^+k
The axis of symmetry lies at x=h
In the given f(x), the value of h is 4
From the given f(x), the axis of symmetry is at x=4
Now we consider the graph of h(x)
The axis of symmetry lies at the x coordinate of vertex
In the graph , vertex is (-2,2)
x coordinate of vertex is -2
Axis of symmetry for h(x) is at x=-2
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