[tex](1)\ y=\dfrac{1}{2}x+3\\\\(2)\ y=x-4\\\\subtitute\ (1)\ to\ (2)\\\\\dfrac{1}{2}x+3=x-4\ \ \ \ |subtract\ 3\ from\ both\ sides\\\\\dfrac{1}{2}x=x-7\ \ \ \ |suntract\ x\ from\ both\ sides\\\\-\dfrac{1}{2}x=-7\ \ \ \ \ |multiply\ both\ sides\ by\ (-2)\\\\\boxed{x=14}\\\\subtitute\ the\ value\ of\ x\ to\ (2):\\\\y=14-4\\\boxed{y=10}[/tex]
Answer: x = 14 and y = 10.
