Respuesta :
Answer:
Total delay is 3037.5 vehicle-min
Maximum queue length is 90
Longest delay under FIFO is 15 min
Longest vehicle delay under LIFO is 52.5 min
Explanation:
Find attachment below
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The time which the queue dissipate is 52.5 minutes, the total delay is 3037.5 vehicles-minute. The longest vehicle delay is in FIFO is 15 minutes and the longest vehicle delay in LIFO is 52.5 minutes
The data given;
Arrival rate
- λ[tex]_1[/tex] = 6 vehicles/ minute from 7:45am - 8:15am
- λ[tex]_2[/tex] = 2 vehicles/ minutes from 8:15am to the rest of the day.
Departure rate
- μ = 2 vehicles / minute.
Time the Queue Dissipates
Arrival curve between 7:45am to 8am
Q[tex]_1[/tex] = 6t
Arrival curve starting from 8:15am to the rest to the rest of the day.
Q[tex]_2[/tex] = 120 + 2t
Departure Curve
Q[tex]_3[/tex] = -90 +6t
set Q[tex]_2[/tex] = Q[tex]_3[/tex] in order to get the value of t; which is the time when the queue dissipates.
Q[tex]_2[/tex] = Q[tex]_3[/tex]
120 + 2t = -90 + 6t
120 + 90 = 6t - 2t
t = 52.5 minutes.
This implies that at 8:37am, the queue completely dissipates.
To calculate the total delay, we may need to integrate
Total Delay
[tex]\int\limits^{30}_0 {6t} \, dt + \int\limits^{52.5}_{30} {(120+2t)} \, dt -\int\limits^{52.5}_{15} {-90+6t} \, dt \\[/tex]
This becomes
[tex]|\frac{6t^2}{2}|_0^3^0 + |120t+ \frac{2t^2}{2}|^5^2^.^5_3_0 - |-90t + \frac{t^2}{2}|^5^2^.^5_1_5[/tex]
Imputing the upper and lower limits;
[tex]2700+9056.25-4500-3543.73-675=3037.5[/tex]
The total delay is 3037.5 vehicle-minute.
Maximum Queue Length
If we want to find the longest queue, following inspecting, the longest queue should be at t =30 minutes.
[tex]Q_m_a_x (t) = Arrivals - Departures\\Q_m_a_x (30) = 90[/tex]
Delay in FIFO
The delay using FIFO (first in, first out) is 15 minutes to arrive
Delay in LIFO
The delay in using LIFO (last in, first out) is 52.5 minutes which is also the time the queue dissipate.
Learn more on rates, FIFO and LIFO here;
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