What is the measure of angle N?

Answer:
∠N = 61°
Step-by-step explanation:
We can use the fact that [tex]\frac{a}{sin(A)}=\frac{b}{sin(B)}=\frac{c}{sin(C)}[/tex] to solve for the missing angle.
In this case, we have [tex]\frac{m}{sin(M)}=\frac{n}{sin(N)}=\frac{o}{sin(O)}[/tex]
So we need to solve for ∠N, so we should manipulate one of the equations that involves the variable N. I will choose to use the equations with N and O since we have the measure of side o
Since [tex]\frac{n}{sin(N)}=\frac{o}{sin(O)}[/tex], solving for N would give us [tex]\frac{nsin(O)}{o} = sin(N)[/tex] and then getting N by itself would give us [tex]N=sin^{-1} (\frac{nsin(O)}{o})[/tex]
Plugging in the respective values would give us [tex]N=sin^{-1} (\frac{18sin(17)}{6}) =sin^{-1} (3sin(17))=sin^{-1} (0.877)= 61.3^{o}[/tex]
∠N = 61°