a)
x = 3, y = - 5, hypotenuse = √[3^2 + 5^2] = √[9+25]=√34
sin = y/hypotenuse = -5/√34
csc = 1/sin = - √34 / 5
cos = x/hypotenuse = 3/√34
sec = 1/cos = √34/3
tan = y/x = -5/3
cotan = 1/tan = -3/5
b) You need to know the x-coordinate of the point and use the same procedure followed above.
