Acceleration is rate of change of velocity.
[tex]\large {\boxed {a = \frac{v - u}{t} } }[/tex]
[tex]\large {\boxed {d = \frac{v + u}{2}~t } }[/tex]
a = acceleration ( m/s² )
v = final velocity ( m/s )
u = initial velocity ( m/s )
t = time taken ( s )
d = distance ( m )
Let us now tackle the problem !
[tex]1 ~ foot = 30.48 ~ cm[/tex]
[tex]1 ~ inch = 2.54 ~ cm[/tex]
[tex]1 ~ foot = 12 ~ inches[/tex]
[tex]\boxed {52.68 ~ feet = 52.68 \times 12 ~ inches = 632.16 ~ inches}[/tex]
[tex]1 ~ day = 24 ~ hours[/tex]
[tex]\boxed {1 ~ hour = 60 ~ minutes}[/tex]
If the dwarf seahorse hippocampus zosterae swims at a rate of 52.68 feet per hour , then :
[tex]52.68 ~ feet/h = \frac{52.68 ~ feet}{1 ~ hour}[/tex]
[tex]52.68 ~ feet/h = \frac{52.68 \times 12 ~ inches}{60 ~ minutes}[/tex]
[tex]52.68 ~ feet/h = \frac{632.16 ~ inches}{60 ~ minutes}[/tex]
[tex]\large {\boxed {52.68 ~ feet/h = 10.536 ~ inches/min} }[/tex]
Grade: High School
Subject: Physics
Chapter: Kinematics
Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate