Given:
[tex]\angle ABC\cong \angle D EF[/tex]
[tex]\angle GHI\cong \angle DE F[/tex]
To prove:
[tex]\angle ABC\cong \angle GHI[/tex]
Solution:
The two common proof is:
Statements Reasons
1. [tex]\angle ABC\cong \angle DE F[/tex] 1. Given
2. [tex]\angle GHI\cong \angle D EF[/tex] 2. Given
3. [tex]\angle ABC\cong \angle GHI[/tex] 3. Transitive property of congruence.
Hence proved.
