Question

The sequence 28, 34, 40, 46, 52, ..., 88 has 11 terms. Find the sum of the 11 terms.
a) 550
c) 610
Ob) 638
od) 288

Answer 1

Answer:

D) 638

Step-by-step explanation:

The pattern shows that they all increase by 6 each time.

The 11 numbers in the pattern would be 28, 34, 40, 46, 52, 58, 64, 70, 76, 82, 88.

Adding all of them together, 28 + 34 + 40 + 46... and so on up to 88. This would equal 638.

Answer 2

The sum of the first 11th term of the sequence is 638

The sequence in question is an arithmetic progression. The formula for finding the sum of an A.P is expressed as:

$S_n=\frac{n}{2}(2a+(n-1)d)$

a is the first term = 28

d is the common difference = 34 - 28 = 40 - 34 = 6

n is the number of terms = 11

Substitute the given parameters into the expression

$S_{11}=\frac{11}{2}(2(28)+(11-1)(6))\\S_{11}=\frac{11}{2}(56+(10((6))\\S_{11}=\frac{11}{2}(116)\\S_{11}=11\times 58\\S_{11}=638$

Hence the sum of the first 11th term of the sequence is 638

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