Instructions: Find the missing length indicated.
I

Answer:
x = 12 units
Step-by-step explanation:
In the picture attached,
Since, DE and BC are the parallel lines,AC and AB are the transverse.
Therefore, ∠AED ≅ ∠ABC [Alternate angles]
∠ADE ≅ ∠ACB [Alternate angles]
ΔADE ~ ΔACB [By AA postulate of similarity]
By the property of similarity,
If two triangles are similar then their corresponding sides will be proportional.
[tex]\frac{\text{AB}}{\text{AE}}=\frac{\text{AC}}{\text{AD}}[/tex]
[tex]\frac{(4+8)}{4}=\frac{(6+x)}{6}[/tex]
[tex]3=1+\frac{x}{6}[/tex]
x = 12
Therefore, length of missing segment is 12 units.