Question

Use the spinner shown to answer the question. Assume that it is equally probable that the pointer will land on any one of the colored regions. If the pointer lands on a​ borderline, spin again.
If the spinner is spun​ once, find the probability that the pointer lands in a region that is red or green.

Answer 1

This question is not complete because it lacks the diagram of the spinner.

Find attached to this answer, the diagram of the spinner

Answer:

5/6

Step-by-step explanation:

In the attached diagram, the spinner is divided into 6 equal sections

3 of those sections are coloured red

2 of those sections are coloured green

1 of those sections is coloured yellow

Hence,

The number of events = The number of equally divided sections = 6

Step 1

The first step would be to find the probability that the spinner would land on the red region

P(Red) = Number of Possible Outcomes(Red) ÷ Number of events

P(Red) = 3/6

Step 2

The second step would be to find the probability that the spinner would land on the green region

P(Green) = Number of Possible Outcomes(Green) ÷ Number of events

P(Green) = 2/6

Step 3

The third and final step would be to to find the probability that the pointer lands in a region that is red or green.

P(Red or Green) = P(Red) + P(Green)

= 3/6 +2/6

P(Red or Green) = 5/6

Therefore, the probability that the pointer lands in a region that is red or green is = 5/6

Answer 2

Using the principle of probability, the probability that the spinner lands on red or green region is 5/6

From the Spinner :

• Total number of regions = 6
• Number of green regions = 2
• Number of red regions = 3

Recall :

• Probability = required outcome / Total possible outcomes

Required outcome = (2 + 3) = 5

P(Green or red) = 5/6

Therefore, the probability is 5/6

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