Respuesta :
Substituting the value of C=$328 into the equation we have
[tex]100+38x=328 [/tex]
[tex]328-100=38x[/tex]
[tex]228=38x[/tex]
[tex]x= \frac{228}{38} [/tex]
[tex]x=6[/tex]
The number line that shown the value of x=6 is the answer
[tex]100+38x=328 [/tex]
[tex]328-100=38x[/tex]
[tex]228=38x[/tex]
[tex]x= \frac{228}{38} [/tex]
[tex]x=6[/tex]
The number line that shown the value of x=6 is the answer
Answer:
x = 6
Step-by-step explanation:
Given : Fiona decides to join a gym :
A joining fee of $100
A monthly fee of $38
x represents the number of months.
Fiona has allocated a maximum of $328 to spend on her gym membership
Her total membership fee for that duration of time: 100 + 38x = C
Solution :
It is given that Fiona has allocated a maximum of $328 to spend
So, C = $328
Putting this value in equation 100 + 38x = C
⇒[tex]100+38x=328[/tex]
⇒[tex]38x=328-100[/tex]
⇒[tex]38x=228[/tex]
⇒[tex]x=\frac{228}{38}[/tex]
⇒[tex]x=6[/tex]
Thus, x = 6 is number line that shows the possible number of months that Fiona can be a member of the gym.