Question

what is the solution to 2x squared + 8x = x squared -16

Answer 1

Answer:

x= -4

Step-by-step explanation:

subtract x² over and add 16 so that the equation is equal to 0 so you get:

x²+ 8x + 16 = 0

then factor,

(x+4)(x+4)=0

solve for x

x+4=0

x=-4

Answer 2

Answer:

$x=-4$

Step-by-step explanation:

$2x^2+8x=x^2-16$

$2x^2+8x+16=x^2-16+16$

$2x^2+8x+16=x^2$

$2x^2+8x+16-x^2=x^2-x^2$

$x^2+8x+16=0$

$x_{1,\:2}=\frac{-8\pm \sqrt{8^2-4\cdot \:1\cdot \:16}}{2\cdot \:1}$

$8^2-4\cdot \:1\cdot \:16$

$=8^2-64$

$=64-64$

$=0$

$x_{1,\:2}=\frac{-8\pm \sqrt{0}}{2\cdot \:1}$

$x=\frac{-8}{2\cdot \:1}$

$\frac{-8}{2\cdot \:1}$

$=\frac{-8}{2}$

$=-4$

$x=-4$