Question

factorise fully the following expression (am-an+bm-bn)​

Answer 1

Step-by-step explanation:

am-an+bm-bn

m(a+b)-n(a+b)

(m-n)(a-b)

Answer 2

Answer:

$\small \sf \: ( m - n ) ( a + b )$

Step-by-step explanation:

( am - an + bm - bn)

• Do the grouping

= ( am - an ) + ( bm - bn )

• Factor out a in the first and b in the second group

= a ( m - n ) + b ( m - n )

• factor out common term m - n by using distributive property

= ( m - n ) ( a + b )