Question

2. If 1.75 L of a gas is at 700. K and is under 250. kPa of pressure, what will the new
volume be if the temperature is lowered to 298K and the pressure is brought down to
53.2 kilopascals?

Answer 1

Answer:

Final volume is 3.50L

Explanation:

It is possible to find volume of a gas using combined gas law:

$\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}$

Where P is pressure, V is volume and T is temperature of 1: initial state and 2: final state

If initial state of the gas is:

1.75L of a gas is at 700K and is under 250kPa of pressure

And final state is:

298K and 53.2kPa.

Replacing:

$\frac{250kPa*1.75L}{700K} =\frac{53.2kPa*V_2}{298K}$

0.625L = 0.1785*V₂

3.50L = V₂

Thus, final volume is 3.50L