If one firecracker produces a sound intensity of 90db, what would be the intensity of a sound produced by 1000 firecrackers, all going off at once?

Respuesta :

Answer:

90db

Explanation:

The 1000, will produce sa.e intensity, since the firecrackers are made of same materials

Answer: additional intensity of 30db result in 120db

Explanation:

Sound intensity is defined as the sound power per unit area in other words, it is the power carried by sound waves per unit area in a direction perpendicular to that area. The common approach to sound intensity measurement is to use the decibel scale to measure the ratio of a given intensity I to the threshold of hearing intensity.

Since log 1000=3

Therefore, 10 log 1000=30 db assuming that the distance is the same in both cases.

result in 120db i.e 90+30 = 120db. Which is painful at that point.

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