Answer:
[tex] \dfrac{3y^8}{11t^2} [/tex]
Step-by-step explanation:
[tex]\dfrac{3y^4t^{-2}}{11y^{-4}} =[/tex]
[tex] = \dfrac{3y^{4 - (-4)}}{11t^2} [/tex]
[tex] = \dfrac{3y^8}{11t^2} [/tex]
