Question

13.6 lbs of a gas occupies 174 ft3 at a certain pressure and temperature. The amount of gas is then increased to 43.8 lbs. What is the new volume for this amount assuming the pressure and temperature haven’t changed? Answer in units of ft .

Answer 1

Answer:

$V_2=54.0ft^3$

Explanation:

Hello,

In this case, we can use the Avogadro's law in order to understand the mole-volume behavior as a directly proportional relationship:

$\frac{V_1}{n_1} =\frac{V_2}{n_2}$

Nonetheless, here we are not given neither the identity of the gas nor its molar or atomic mass, for that reason we can apply the aforementioned equation in terms of mass as we are talking about the same gas:

$\frac{V_1}{m_1} =\frac{V_2}{m_2}$

In such a way, the new volume turns out:

$V_2=\frac{V_1m_2}{m_1} =\frac{174ft^3*13.6lbs}{43.8lbs} \\\\V_2=54.0ft^3$

Best regards.