Answer:
With a 85% confidence level you'd expect the teenage boys to be on average between [29.217; 30.783]cm taller than the girls.
Step-by-step explanation:
Hello!
Given the variables:
X₁: height of a teenage boy.
n₁= 46
[tex]\frac{}{X}[/tex]₁= 195cm
S₁²= 58cm²
X₂= height of a teenage girl
n₂= 66
[tex]\frac{}{X}[/tex]₂= 165cm
S₂²= 75cm²
If the boys are taller than the girls then you'd expect μ₁ > μ₂ or expressed as a difference between the two population means: μ₁ - μ₂ > 0
To estimate the difference between both populations you have to calculate the following interval:
([tex]\frac{}{X}[/tex]₁- [tex]\frac{}{X}[/tex]₂) + [tex]t_{n_1+n_2-2; 1-\alpha /2}[/tex] * [tex]\sqrt{\frac{S_1}{n_1} +\frac{S_2}{n_2} }[/tex]
[tex]t_{n_1+n_2-2; 1-\alpha /2}= t_{110; 0.925}= 1.450[/tex]
Point estimate: ([tex]\frac{}{X}[/tex]₁- [tex]\frac{}{X}[/tex]₂) = (195-165)= 30
Margin of error:[tex]t_{n_1+n_2-2; 1-\alpha /2}[/tex] * [tex]\sqrt{\frac{S_1}{n_1} +\frac{S_2}{n_2} }[/tex]= 1.450*0.54= 0.783
30 ± 0.783
[29.217; 30.783]
With a 85% confidence level you'd expect the teenage boys to be on average between [29.217; 30.783]cm taller than the girls.
I hope this helps!