Respuesta :
Answer
Given series,
12 + 18 + 24 + 30 + . . . + 198
first term of series, a = 12
common difference,d = 18- 12 = 6
Last term of the series, a_n or l = 198.
a) The expression of arithmetic sequence given by the explicit rule is
[tex]a_n = a + (n-1)d[/tex]
[tex]a_n = 12 + (n-1)6[/tex]
b) number of terms in the series
[tex] 198 = 12 + (n-1)6[/tex]
[tex] n-1 = 31[/tex]
[tex]n = 32[/tex]
c) value of the series
[tex] S_n = \dfrac{n}{2}(a+l)[/tex]
[tex] S_n = \dfrac{32}{2}(12+198)[/tex]
[tex] S_n = 3360[/tex]
Answer:
1.) an= 12 + (n-1) 6
2.) n = 32
3.) C. 3,360
Step-by-step explanation: