Question

The population of a fish farm in t years is modeled by the equation P(t)= 1000/1+9e^0.6t what is the intial population of fish

Answer 1

Answer:

The initial population of fish is 100.

Step-by-step explanation:

The population of a fish farm is modeled by the following equation:

$P(t) = \frac{1000}{1 + 9e^{0.6t}}$

What is the intial population of fish

This is P(0)

Any non-zero value elevated to zero is 1. So

$P(0) = \frac{1000}{1 + 9e^{0.6*0}} = \frac{1000}{1 + 9e^{0}} = \frac{1000}{10} = 100$

Answer 2

Answer:

The initial population is 100 fish

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Population of a fish farm in t years is modeled by the equation:

P(t) = 1000/1+9e^0.6t

2. What is the initial population of fish?

We will substitute t by 0 in the exponential growth equation, to find out the initial population, this way:

P(0) = 1000/1+9e^0.6*0

P(0) = 1000/1+9e^0

P(0) = 1000/1+9*1 (e^0 = 1)

P(0) = 1000/10

P(0) = 100