Question

A firm makes a time study of a process that has only one step. A total of 50 observations are​ made, and the total time recorded for these 50 obserations is 957 seconds. The performance rating for the observations is 105 percent and the allowance for the process is 18 percent of normal time. What is the standard time for the​ process?

Answer 1

Answer:

24.5 seconds

Explanation:

Given that:

Total number of observations = 50

Total time recorded for these 50 observations = 957 seconds.

The average observed time  = $\frac{Total time recorded for these 50 observations}{Total number of observations}$ = $\frac{957}{50}$ = 19.14

Next we determine the Normal Time:

Normal Time = average observed time× performance rating for the observations

Recall that the performance rating is 105% =1.05

Normal Time = 19.14 × 1.05 = 20.097

The standard time of a job is obtained by adding various allowances to the basic or normal time of the job.

Computing the standard time:

Standard time = $\frac{Normal Time}{1 - allowance factor}$ = $\frac{20.097}{1 - 0.18}$ = $\frac{20.097}{0.82}$= 24.5

The standard time for the​ process is 24.5 seconds