Question:
The pressure and temperature inside a bike tire is 10 atm and 10 K
respectively. What will the pressure become in the tire when the temperature is increased 20 K?
Answer:
The pressure will be 20 atm
Explanation:
Here we are given;
Initial pressure, P₁ = 10 atm
Initial Temperature, T₁ = 10 K
Final Temperature, T₂ = 20 K
Final pressure, P₂ = Required
We note that according to Gay Lussac's Law, the pressure of a given mass of gs is directly proportional to its temperature in Kelvin
That is P ∝ T, and
[tex]\frac{P_1}{T_1} = \frac{P_2}{T_2}[/tex]
Therefore;
[tex]{P_2} = \frac{P_1 \times {T_2}}{T_1} = \frac{10 \times {20}}{10} = 20 \ atm[/tex]
The pressure will be 20 atm.