Answer:
There is enough evidence to support the claim that internet users spend less time watching television.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 154.8 minutes per day
Sample mean, [tex]\bar{x}[/tex] = 128.7 minutes
Sample size, n = 50
Alpha, α = 0.05
Sample standard deviation, s = 46.5 minutes
First, we design the null and the alternate hypothesis
[tex]H_{0}: \mu = 154.8\text{ minutes per day}\\H_A: \mu < 154.8\text{ minutes per day}}[/tex]
We use one-tailed t test to perform this hypothesis.
Formula:
[tex]t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }[/tex]
Putting all the values, we have
[tex]t_{stat} = \displaystyle\frac{128.7 - 154.8}{\frac{46.5}{\sqrt{50}} } = -3.9689[/tex]
Critical Value:
Now, [tex]t_{critical} \text{ at 0.05 level of significance, 49 degree of freedom } = -1.6765[/tex]
Conclusion:
Since, the calculated test statistic is smaller than the critical value, we fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.
Thus, there is enough evidence to support the claim that internet users spend less time watching television.