Step-by-step explanation:
BC is tangent to the circle with center A at point C and AC is radius.
[tex] \therefore AC \perp BC\\
\therefore \angle ACB =90°\\[/tex]
Now by Pythagorean theorem:
[tex] AB^2 = AC^2 + BC^2 \\
\therefore AC^2 = AB^2-BC^2\\
\therefore x^2 = 17^2-14^2\\
\therefore x^2 =289-196\\
\therefore x^2 =93\\
\therefore x =\sqrt{93}\\
\therefore x =9.64365076\\
\huge \purple {\boxed {\therefore x = 9.64\: units}} [/tex]
