27-08-2017
Mathematics

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The problem in the middle...how do you solve? The one that starts 27 1/3 [....

The problem in the middlehow do you solve The one that starts 27 13 class=

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coolstick coolstick

27-08-2017

In PEMDAS, we do parenthesis first, so 2+4=6. Next, we have exponents. The cube root of 27 is 3, the square root of 4 is 2, and 6^2=36, getting
3*sqrt(36-6(4))=3*(sqrt(12))

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