Question

Find the minimum acceleration attained on the interval 0<=t<=4 by the particale whos velocity is given by v(t)=t^2-4t^2-3t+3

Answer 1

we  know that vt = t^2 - 4t^2 - 3t + 3

a = v' = 3t^2 - 8t - 3

a'=  6t - 8 = 0

6t = 8

t = 8/6

hope this helps