Respuesta :

[tex]f(t)=2t^3+t\\\\f'(t)=3\cdot2t^{3-1}+1=6t^2+1\\\\\boxed{f'(a)=6a^2+1}[/tex]
using derivations laws 
f(t) = 2t^3 + t
f'(t)=6t^2+1
substituting a instead of t
f'(a)=6a^2+1
hope it helps
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