Question

What is the simplified form of 1 over x–cubed all over 3 over x squared ?.

Answer 1

Dividing fractions means to invert ( flip over ) the second fraction and multiply:
$\frac{ \frac{1}{ x^{3} } }{ \frac{3}{ x^{2} } } = \frac{1}{ x^{3} } : \frac{3}{ x^{2} } = \\ \frac{1}{ x^{3} } * \frac{ x^{2} }{3}= \frac{1}{3x}$
Answer:   1 / 3x

Answer 2

Answer:  Simplified form is $\frac{1}{3x}$

Step-by-step explanation:

Since we have given that

$\frac{\frac{1}{x^3}}{\frac{3}{x^2}}$

We need to simplify the above expression:

By using "Exponential rule":

$a^m\div a^n=a^{m-n}$

$\frac{\frac{1}{x^3}}{\frac{3}{x^2}}\\\\=\frac{1}{x^3}\times \frac{x^2}{3}\\\\=\frac{1}{3}\times \frac{x^2}{x^3}\\\\=\frac{1}{3x^{3-2}}\\\\=\frac{1}{3x}$

Hence, Simplified form is $\frac{1}{3x}$