Question

Elle is pushing a box of mass 7.0 kilograms with the force of 25 newtons. If the force of friction is 2.6 newtons, what is the value of acceleration of the box?. . A. 0.7. B. 2.6. C. 3.2 . D . 3.6

Answer 1

F = Force
m = Mass
a = Acceleration

F = m.a 

(25 - 2.6) N =7kg . a

22.4 N = 7kg . a

a =  22.4 / 7
   =. 3.2

Which means the answer is option C.

hope this helps

Answer 2

resultant force = applied force - friction = 25N - 2.6N = 22.4N According to Newton's second law F = ma 22.4N = 7 Kg*a a = 22.4/7 = 3.2 m/s^2