Question

If the coefficient of friction for a drag racer's tires on concrete is 1.2 and the drag racer weighs 10,000 N, how much friction force pushes the care forward?

Answer 1

Answer:

12kN

Explanation:

Remembering that Force is proportional to Reaction force and coefficient of friction.

$F = \mu R\\F = 1.2 * 10000\\F = 120000N$