Question

y = x^2 - 2x; domain {-3, 0, 5}

Answer 1

Answer:

range:{0,15}

Step-by-step explanation:

y=x²-2x

domain:{-3,0,5}

for range

when x=-3

y=(-3)²-2×(-3)=9+6=15

when x=0

y=0-0=0

when x=5

y=5²-2×5=25-10=15

range:{0,15}

or

y=x²-2x+1-1=(x-1)²-1

when x=-3

y=(-3-1)²-1=16-1=15

when x=0

y=(0-1)²-1=1-1=0

when x=5

y=(5-1)²-1=16-1=15