Question

what is the equation of the line that passes through (-3, -1) and has a slope of 3/5 ? put your answer in slope-intercept form.

Answer 1

$The\ slope-point\ form:y-y_1=m(x-x_1)\\The\ slope-intercept\ form:y=mx+b\\--------------------\\m=\dfrac{3}{5};\ (-3;-1)\to x_1=-3\ and\ y_1=-1\\\\y-(-1)=\dfrac{3}{5}(x-(-3))\\y+1=\dfrac{3}{5}(x+3)\\y+1=\dfrac{3}{5}x+\dfrac{9}{5}\ \ \ \ |subtract\ 1=\dfrac{5}{5}\ from\ both\ sides\\\\\boxed{y=\dfrac{3}{5}x+\dfrac{4}{5}}$