Question

In 1992, the U.S. Senate was composed of 57 Democrats and 43 Republicans. Of the Democrats, 38 had served in the military, whereas 28 of the Republicans had served. If a senator selected at random is found to have served in the military, what is the probability that the senator is Republican

Answer 1

Answer:

42.42% probability that the senator is Republican

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Desired outcomes:

Republican senator having served in the military, so $D = 28$

Total outcomes:

Senators who served in the military(because the senator is found to have served). So $T = 38+28 = 66$

Probability:

$p = \frac{D}{T} = \frac{28}{66} = 0.4242$

42.42% probability that the senator is Republican

Answer 2

Answer: 0.66

Step-by-step explanation:

The United States senate had 57 Democrats and 43 Republicans which makes the total numerous of senators 100.

38 Democrats had served in the military while 28 Republicans has served in the military which makes the total number of senators that had served in the military 66.

Probability of a Republican senator that had served in the military will be: