HELP. It’s LOG form. Since were out of school I forgot how I did this and it’s due so it would be a life saver.

HELP Its LOG form Since were out of school I forgot how I did this and its due so it would be a life saver class=

Respuesta :

Answer:

see below

Step-by-step explanation:

exponent to log: [tex]a^b[/tex] = c ---> logₐc = b

ie. question 6

log ₁₀(3x+1) = 2 -----> [tex]10^{2} = 3x+1[/tex]

that will get you through questions 1 to 3, 5 to 6, and 8

in question 4, all you have to do is know that 2^2 = 4 and 2^3 = 8, by setting the bases equal, you can manipulate the exponents to get 2x+8 = 3x-3

for questions 7 and 9,

remember that:

logₐc + logₐd = logₐ(cd)

logₐc - logₐd = logₐ([tex]\frac{c}{d}[/tex])

remember change of base is [tex]log_{a} b = \frac{log_xb}{log_xa}[/tex], this will be useful if you need your calculator since calculators only have base 10 and maybe if your calculator is good enough natural base e