Question

PLEASEE HELP ANYONE
Given the bag of marbles above, find the probability of first drawing a green marble and then drawing a blue marble, without replacing the first marble.

Answer 1

We notice there are 4B and 4G (shown in the photo)

P(picking 1st a Green) = 4/8 (having picked a green -and not replacing it- the remaining number of marbles is 3G + 4B)

P(picking 2nd a Green) =3/7

P(picking 1st green AND picking 2nd Green )=(4/8) x (3/7) = 12/56≈ 0.21=21%

Answer 2

Answer: 16/56 = 29%

Step-by-step explanation:

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