Answer:
The index of refraction for Medium 2 would be 1.25
Step-by-step explanation:
We have the following data:
Speed of light in Medium 1 = V₁
Speed of light in Medium 2 = V₂
The speed of Light in Medium 2 is related to speed of light in Medium 1 as:
V₂ = 0.8 V₁
Moreover, it is given that Medium 1 is air with index of refraction equal to 1. i.e.
n₁ = 1
We need to find the index of refraction for medium 2. Lets name it is as n₂.
Snell's law related the above mentioned 4 quantities by following relation:
The ratio of indices of refraction of 2 mediums is equivalent to the reciprocal of ratio of phase velocities in those 2 mediums. Mathematically, this can be written as:
[tex]\frac{n_{1}}{n_{2}} = \frac{V_{2}}{V_{1}}[/tex]
Substituting the values we have gives us:
[tex]\frac{1}{n_{2}}=\frac{0.8V_{1}}{V_{1}} \\\\\frac{1}{n_{2}}=0.8\\\\ 1=0.8n_{2}\\\\\frac{1}{0.8}=n_{2}\\\\ n_{2}=1.25[/tex]
This means, the index of refraction for Medium 2 would be 1.25