Answer:
the error in conductor 1 (120 Ω)is 0.33%
the error in conductor 2 (350 Ω) is 0.11%
meanwhile, the current is constant.
Explanation:
Given:
initial gage resistance = 120 Ω and 350 Ω
conductor = 26 AWG
resistance = 20.4 Ω and 1000 feet
if 20 feet length of two conductor, each conductor has a resistance equal to
(20.4/1000 ft) Ω
the change in resistance in conductor is equal to
(20 * 20)/1000 = 400/1000
thus the error is 0.4 Ω
the error in conductor 1 (120 Ω)is
(0.4/120) * 100 = 0.33%
the error in conductor 2 (350 Ω) is
(0.4/350) * 100 = 0.11%
meanwhile, the current is constant.