Question

Find the area of a regular Octagon with an apothem of 9.6 m and sides of length 8.

Answer 1

Area of regular Octagon is 614.4 $m^2$

Step-by-step explanation:

Given ,

apothem / height of triangle  -  9.6 m

length of side = 8 m

Area of Regular Octagon = 8 *base * height

⇒ 8*9.6*8

⇒ 614.4 $m^2$

Area of regular Octagon is 614.4 $m^2$.