Let ∠D be an acute angle such that sinD=0.75. Use a calculator to approximate the measure of ∠D to the nearest tenth of a degree.

What is the measure of
Please show all the work on how you got your answer.

Let D be an acute angle such that sinD075 Use a calculator to approximate the measure of D to the nearest tenth of a degree What is the measure of Please show a class=

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r3t40

If [tex]\sin(D)=0.75[/tex] then [tex]\arcsin(0.75)=D\approx48.59^{\circ}[/tex]

Hope this helps.

For finding the measure of angle when a trigonometric ratio is given, we use inverse trigonometric functions.

The measure of ∠D is [tex]\angle D \approx 48.59^{\circ}[/tex]

How to find the measure of angle D using trigonometric ratios?

For finding the measure of angle when a trigonometric ratio is given, we use inverse trigonometric functions.

For example, for sine there lies arcsin, for cos, there lies arccos and so on.

Thus,

[tex]sin(D) = 0.75\\\angle D = arcsin(0.75) \in \{ 48.59, 131.409\}[/tex]

But since ∠D is acute, thus we have [tex]\angle D \approx 48.59^{\circ}[/tex]

Thus, the measure of ∠D is  [tex]\angle D \approx 48.59^{\circ}[/tex]

Learn more about inverse trigonometric ratio arcsin here:

https://brainly.com/question/1634690

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