For finding the measure of angle when a trigonometric ratio is given, we use inverse trigonometric functions.
The measure of ∠D is [tex]\angle D \approx 48.59^{\circ}[/tex]
How to find the measure of angle D using trigonometric ratios?
For finding the measure of angle when a trigonometric ratio is given, we use inverse trigonometric functions.
For example, for sine there lies arcsin, for cos, there lies arccos and so on.
Thus,
[tex]sin(D) = 0.75\\\angle D = arcsin(0.75) \in \{ 48.59, 131.409\}[/tex]
But since ∠D is acute, thus we have [tex]\angle D \approx 48.59^{\circ}[/tex]
Thus, the measure of ∠D is [tex]\angle D \approx 48.59^{\circ}[/tex]
Learn more about inverse trigonometric ratio arcsin here:
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