Answer:
1228.8 g of O₂ are needed in the reaction
Explanation:
Combustions reactions make CO₂ and H₂O as products. Let's make the reaciton:
C₅H₁₂ + 8O₂ → 5CO₂ + 6H₂O
Oxygen is always one of the reactants
You have 4.80 moles of pentane. Let's make the rule of three (ratio is 1:8)
1 moles of pentane needs 8 moles of oxygen to react
Therefore 4.80 moles will react with (4.80 . 8) /1 = 38.4 moles
We convert the moles to mass: 38.4 mol . 32 g / 1mol = 1228.8 g of O₂
